New rod differential

[Feliks]

Well, I see that I need to do the mathematical calculations step by step ...
so we have a 14m x 20m x 10m = 2800m ^ 3 bucklet ... he gives STRING at these 80 degrees Celsius those 500 KG of strength ... in a line, ALL bucklets give a total thrust of 12 x 500 KG = 6000 KG .
Now the pulling wheels have a diameter of 20 meters, i.e. a radius of 10 meters .. So we get a torque of 6000 x 10 m = 60,000 Kgm.
The circulation time of 1 bouquet is 100 seconds on this road 500 meters. or 500 meters divided by the circumference of the wheel, i.e. PI x D, 3, 14 x 20 m = 62 m, i.e. 500m / 62m = 8 turns, to overcome this path ... So one turn, that is 100 seconds / 8 = 12, 4 seconds lasts, i.e. 60 / 12.4 = 4.83 RPM per minute, on the wheel shaft,
The power we get with such parameters is 4, 63 rev / min x 60,000 kgm = 335 HP.

But now we can build it in a shaft dug in the ground, every 1000 meters deep, which is not a problem, and still part above the ground ..
And of course further permutations ..




Andrew